Big Sorting

Problem Statement :

Consider an array of numeric strings where each string is a positive number with anywhere from 1 to 10^6  digits. Sort the array's elements in non-decreasing, or ascending order of their integer values and return the sorted array.


Return the array ['1', '3', '150', '200'].

Function Description

Complete the bigSorting function in the editor below.

bigSorting has the following parameter(s):

string unsorted[n]: an unsorted array of integers as strings

string[n]: the array sorted in numerical order
Input Format

The first line contains an integer, n, the number of strings in unsorted.
Each of the n subsequent lines contains an integer string, unsorted[ i ].


1  <=  n  <=  2x10^5
Each string is guaranteed to represent a positive integer.
There will be no leading zeros.
The total number of digits across all strings in  is between  and  (inclusive).

Solution :


                            Solution in C :

In   C++  :


using namespace std;

#define forn(i,n) for(int i=0;i<(int)(n); i++)
#define forsn(i,s,n) for(int i=(s);i<(int)(n); i++)
#define esta(x,v) (find((v).begin(),(v).end(),(x)) !=  (v).end())
#define index(x,v) (find((v).begin(),(v).end(),(x)) - (v).begin())
#define debug(x) cout << #x << " = "  << x << endl
#define pb push_back
#define mp make_pair

typedef long long tint;
typedef unsigned long long utint;
typedef long double ldouble;

typedef vector<int> vint;

int toNumber (string s)
	int Number;
	if ( ! (istringstream(s) >> Number) ) Number = 0; 
	return Number;

string toString (int number)
    ostringstream ostr;
    ostr << number;
    return  ostr.str();

int main (){
	int n;
	vector< pair<int, string> > v;
		string s;
		v.pb(mp((int)s.size(), s));
	sort(v.begin(), v.end());
	forn(i, n){

In   Java  :

import java.util.Arrays;
import java.util.Comparator;
import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(;
        int n = in.nextInt();
        String[] unsorted = new String[n];
        for (int unsorted_i = 0; unsorted_i < n; unsorted_i++) {
            unsorted[unsorted_i] =;

        Arrays.sort(unsorted, new Comparator<String>() {
            public int compare(String o1, String o2) {
                if (o1.length() < o2.length()) {
                    return -1;
                if (o1.length() > o2.length()) {
                    return 1;
                return o1.compareTo(o2);

        for (String s : unsorted) {

In   C  :

#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int cmp(const void *p, const void *q)
    char* s1 = *(char**)p;
    char* s2 = *(char**)q;
    int s1l=strlen(s1);
    int s2l=strlen(s2);
    	return 1;
    	return -1;
    int i,flag=0;
    	return s1[i]-s2[i];
    return 0;

int main(){
    int n,i,tl;
    char* str[n];
    char temp[1000001];
    return 0;

In  Python3 :

import sys

n = int(input().strip())
unsorted = []
unsorted_i = 0
for unsorted_i in range(n):
   unsorted_t = str(input().strip())

unsorted.sort(key = lambda x : int(x))
for u in unsorted:

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