Big Sorting
Problem Statement :
Consider an array of numeric strings where each string is a positive number with anywhere from 1 to 10^6 digits. Sort the array's elements in non-decreasing, or ascending order of their integer values and return the sorted array. Example Return the array ['1', '3', '150', '200']. Function Description Complete the bigSorting function in the editor below. bigSorting has the following parameter(s): string unsorted[n]: an unsorted array of integers as strings Returns string[n]: the array sorted in numerical order Input Format The first line contains an integer, n, the number of strings in unsorted. Each of the n subsequent lines contains an integer string, unsorted[ i ]. Constraints 1 <= n <= 2x10^5 Each string is guaranteed to represent a positive integer. There will be no leading zeros. The total number of digits across all strings in is between and (inclusive).
Solution :
Solution in C :
In C++ :
#include<iostream>
#include<fstream>
#include<math.h>
#include<algorithm>
#include<string>
#include<map>
#include<vector>
#include<queue>
#include<stack>
#include<sstream>
#include<set>
using namespace std;
#define forn(i,n) for(int i=0;i<(int)(n); i++)
#define forsn(i,s,n) for(int i=(s);i<(int)(n); i++)
#define esta(x,v) (find((v).begin(),(v).end(),(x)) != (v).end())
#define index(x,v) (find((v).begin(),(v).end(),(x)) - (v).begin())
#define debug(x) cout << #x << " = " << x << endl
#define pb push_back
#define mp make_pair
typedef long long tint;
typedef unsigned long long utint;
typedef long double ldouble;
typedef vector<int> vint;
int toNumber (string s)
{
int Number;
if ( ! (istringstream(s) >> Number) ) Number = 0;
return Number;
}
string toString (int number)
{
ostringstream ostr;
ostr << number;
return ostr.str();
}
int main (){
int n;
cin>>n;
vector< pair<int, string> > v;
forn(i,n){
string s;
cin>>s;
v.pb(mp((int)s.size(), s));
}
sort(v.begin(), v.end());
forn(i, n){
cout<<v[i].second<<endl;
}
}
In Java :
import java.util.Arrays;
import java.util.Comparator;
import java.util.Scanner;
public class Solution {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
String[] unsorted = new String[n];
for (int unsorted_i = 0; unsorted_i < n; unsorted_i++) {
unsorted[unsorted_i] = in.next();
}
Arrays.sort(unsorted, new Comparator<String>() {
@Override
public int compare(String o1, String o2) {
if (o1.length() < o2.length()) {
return -1;
}
if (o1.length() > o2.length()) {
return 1;
}
return o1.compareTo(o2);
}
});
for (String s : unsorted) {
System.out.println(s);
}
}
}
In C :
#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>
int cmp(const void *p, const void *q)
{
char* s1 = *(char**)p;
char* s2 = *(char**)q;
int s1l=strlen(s1);
int s2l=strlen(s2);
if(s1l>s2l)
return 1;
if(s2l>s1l)
return -1;
int i,flag=0;
for(i=0;i<s1l;i++)
{
if(s1[i]==s2[i])
continue;
else
{
flag=1;
break;
}
}
if(flag)
{
return s1[i]-s2[i];
}
return 0;
}
int main(){
int n,i,tl;
scanf("%d\n",&n);
char* str[n];
char temp[1000001];
for(i=0;i<n;i++)
{
scanf("%s",temp);
tl=strlen(temp);
str[i]=malloc(sizeof(char)*(tl+1));
strcpy(str[i],temp);
}
qsort((void*)str,n,sizeof(str[0]),cmp);
for(i=0;i<n;i++)
printf("%s\n",str[i]);
return 0;
}
In Python3 :
import sys
n = int(input().strip())
unsorted = []
unsorted_i = 0
for unsorted_i in range(n):
unsorted_t = str(input().strip())
unsorted.append(unsorted_t)
unsorted.sort(key = lambda x : int(x))
for u in unsorted:
print(u)
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