ASCII String to Integer - Amazon Top Interview Questions
Problem Statement :
You are given a string s containing digits from "0" to "9" and lowercase alphabet characters. Return the sum of the numbers found in s. Constraints 1 ≤ n ≤ 100,000 where n is the length of s Example 1 Input s = "11aa32bbb5" Output 48 Explanation Since 11 + 32 + 5 = 48. Example 2 Input s = "abc" Output 0 Explanation There's no digits so it defaults to 0. Example 3 Input s = "1a2b30" Output 33 Explanation Since 1 + 2 + 30 = 33.
Solution :
Solution in C++ :
int solve(string s) {
int curr = 0, ret = 0;
for (auto &ch : s) {
if (isdigit(ch)) {
curr = curr * 10 + ch - '0';
} else {
ret += curr;
curr = 0;
}
}
ret += curr;
return ret;
}
Solution in Java :
import java.util.*;
class Solution {
public int solve(String s) {
int cur = 0;
int ans = 0;
for (char c : s.toCharArray()) {
if (Character.isDigit(c))
cur = 10 * cur + (int) (c - '0');
else {
ans += cur;
cur = 0;
}
}
ans += cur;
return ans;
}
}
Solution in Python :
class Solution:
def solve(self, s):
ret = 0
curr = 0
for ch in s:
if ch in digits: # string.digits
curr = 10 * curr + int(ch)
else:
ret += curr
curr = 0
return ret + curr
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