XOR Strings


Problem Statement :


In this challenge, the task is to debug the existing code to successfully execute all provided test files.

Given two strings consisting of digits 0 and 1 only, find the XOR of the two strings.

To know more about XOR Click Here

Debug the given function strings_xor to find the XOR of the two given strings appropriately.

Note: You can modify at most three lines in the given code and you cannot add or remove lines to the code.

To restore the original code, click on the icon to the right of the language selector.

Input Format

The input consists of two lines. The first line of the input contains the first string, s, and the second line contains the second string, t.


Constraints

1  <=   | s |  <=  10^4
| s |  =  | t |

Output Format

Print the string obtained by the XOR of the two input strings in a single line.


Solution :



title-img 


                            Solution in C :

In  C++  :






#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

string strings_xor(string s, string t) {
    
    string res = "";
    for(int i = 0; i < s.size(); i++) {
        if(s[i] == t[i])
            res += '0';
        else
            res += '1';
    }
    
    return res;
}

int main() {
    string s, t;
    cin >> s >> t;
    cout << strings_xor(s, t) << endl;
    return 0;
}








In    Java  :







import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {
    
    public static String stringsXOR(String s, String t) {
        String res = new String("");
        for(int i = 0; i < s.length(); i++) {
            if(s.charAt(i)== t.charAt(i))
                res = res+"0";
            else
                res =res+ "1";
        }
        
        return res;
    }
    
    public static void main(String[] args) {
    
        String s, t;
        Scanner in = new Scanner(System.in);
        s = in.nextLine();
        t = in.nextLine();
        System.out.println(stringsXOR(s, t));
        
    }
    
}








In    Python3 





def strings_xor(s, t):
    res = ""
    for i in range(len(s)):
        if s[i] == t[i]:
            res += '0'
        else:
            res += '1'
            
    return res
  
s = input()
t = input()
print(strings_xor(s, t))








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