# Utopian Tree

### Problem Statement :

```The Utopian Tree goes through 2 cycles of growth every year. Each spring, it doubles in height. Each summer, its height increases by 1 meter.

A Utopian Tree sapling with a height of 1 meter is planted at the onset of spring. How tall will the tree be after  growth cycles?

For example, if the number of growth cycles is n = 5, the calculations are as follows:

Period  Height
0          1
1          2
2          3
3          6
4          7
5          14

Function Description

Complete the utopianTree function in the editor below.

utopianTree has the following parameter(s):

int n: the number of growth cycles to simulate

Returns

int: the height of the tree after the given number of cycles

Input Format

The first line contains an integer, t, the number of test cases.
t subsequent lines each contain an integer, n, the number of cycles for that test case.

Constraints
1 <= t <= 10
0 <= n <= 60```

### Solution :

```                            ```Solution in C :

python 3  :

#!/usr/bin/env python

import sys

if __name__ == '__main__':

for _ in range(T):
height = 1

for i in range(N):
if i % 2 == 0:
height *= 2
else:
height += 1

print(height)

Java  :

import java.util.Scanner;
import java.util.Vector;

public class Solution {
public static void main(String[] args) {
Scanner stdin = new Scanner(System.in);
int numCases = stdin.nextInt();
Vector<Long> cache = new Vector<>();
for (int i = 0; i < numCases; i++) {
int numCycles = stdin.nextInt();
while(cache.size() <= numCycles) {
if (cache.size() % 2 == 0) {
} else {
}
}
System.out.println(cache.get(numCycles));
}
}
}

C ++  :

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {
int T;
cin >> T;
for(int t = 0; t<T; t++){
int N;
cin >> N;
int ht = 1;
for(int i=0;i<N;i++){
if(i%2==0) ht*=2;
else ht++;
}
cout << ht << endl;
}
return 0;
}

C  :

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {

/* Enter your code here. Read input from STDIN. Print output to STDOUT */
int t,i,n;
scanf("%d",&t);
while(t>0)
{
int h=1;
scanf("%d",&n);
for(i=1;i<=n;i++)
{
if(i%2==1)
h=2*h;
else
h=h+1;
}
printf("%d\n",h);
t=t-1;
}
return 0;
}```
```

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