Swappable Trees - Amazon Top Interview Questions


Problem Statement :


Given two trees root0 and root1, return whether you can transform root0 into root1 by swapping any node's left and right subtrees any number of times.

Example 1

Input

root0 = [1, [3, null, null], [4, [0, null, [2, null, null]], null]]
root1 = [1, [3, null, null], [4, [0, null, [2, null, null]], null]]

Output

True



Solution :



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                        Solution in C++ :

bool solve(Tree* root0, Tree* root1) {
    if (!root0 and !root1) return true;
    if (!root0 or !root1 or root0->val != root1->val) return false;
    return (solve(root0->left, root1->left) and solve(root0->right, root1->right)) or
           (solve(root0->right, root1->left) and solve(root0->left, root1->right));
}
                    




                        Solution in Python : 
                            
class Solution:
    def solve(self, source, target):
        if not source or not target:
            return not source and not target
        t = self.isSubtree(target, source)
        return t

    def isSubtree(self, s, t):
        if not s:
            return False
        elif self.sametree(s, t):
            return True
        else:
            return self.isSubtree(s.right, t) or self.isSubtree(s.left, t)

    def sametree(self, s, t):
        if not s or not t:
            return not s and not t
        elif s.val == t.val:
            return (self.sametree(s.left, t.left) and self.sametree(s.right, t.right)) or (
                self.sametree(s.right, t.left) and self.sametree(s.left, t.right)
            )
        else:
            return False
                    


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