Sum of Digits


Problem Statement :


You're given an integer N. Write a program to calculate the sum of all the digits of N.

Input

The first line contains an integer T, the total number of testcases. Then follow T lines, each line contains an integer N.

Output

For each test case, calculate the sum of digits of N, and display it in a new line.

Constraints
1 ≤ T ≤ 1000
1 ≤ N ≤ 1000000


Example


Input

3 
12345
31203
2123

Output

15
9
8


Solution :



title-img 


                            Solution in C :

#include <stdio.h>

int main(void) {
	int t;
	scanf("%d",&t);
	while (t--){
	    int n,m,sum=0;
	    scanf ("%d",&n);
	    while(n>0){
	        
	        m=n%10;
	        n=n/10;
	    
	        sum=sum+m;
	    }
	        printf("%d\n",sum);
	    
	    
	    
	    
	    
	    
	}
	
	
	return 0;
}
                        


                        Solution in C++ :

#include <iostream>
using namespace std;

int main() 
{
    int t;
    cin>>t;
    
    while(t--)
    {
        int n;
        cin>>n;
        
        int sum=0;
        
        while(n>0)
        {
            sum+=(n%10);
            n/=10;
        }
        
        cout<<sum<<"\n";
        
    }
	return 0;
}
                    


                        Solution in Java :

import java.util.*;
class Main{
    public static void main(String[] args){
        try
        {
        Scanner sc = new Scanner(System.in);
       int n = sc.nextInt();
        for(int i=0;i<n;i++){
            int a = sc.nextInt();
            int sum = 0 ;
            while(a>0){
            int temp = a%10;
            sum +=temp;
            a/=10;
            }
            System.out.println(sum);
        }
        }
        catch(Exception e)
        {
            return;
        }
    }
}
                    


                        Solution in Python : 
                            
T=int(input())
for i in range(T):
    num=int(input())
    sum=0
    for j in str(num):
        sum+=int(j)
    print(sum)


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