**Split List - Microsoft Top Interview Questions**

### Problem Statement :

Given a list of integers nums, return whether you can partition the list into two non-empty sublists such that every number in the left sublist is strictly less than every number in the right sublist. Constraints n ≤ 100,000 where n is the length of nums. Example 1 Input nums = [5, 3, 2, 7, 9] Output True Explanation We can split the list into left = [5, 3, 2] and right = [7, 9]

### Solution :

` ````
Solution in C++ :
bool solve(vector<int>& nums) {
if (nums.size() <= 1) return false;
int max = nums[0]; // max seen so far
int leftMax = nums[0]; // max in the left sublist
int leftSize = 1;
for (int i = 1; i < nums.size(); i++) {
// update max seen so far
max = nums[i] > max ? nums[i] : max;
if (nums[i] <= leftMax) {
// expand left
leftSize = i + 1;
leftMax = max;
}
}
// true if leftSize is not numsSize
return leftSize < nums.size();
}
```

` ````
Solution in Java :
import java.util.*;
class Solution {
public boolean solve(int[] nums) {
int rmin[] = new int[nums.length];
rmin[nums.length - 1] = nums[nums.length - 1];
for (int i = nums.length - 2; i > -1; i--) {
if (nums[i] < rmin[i + 1])
rmin[i] = nums[i];
else
rmin[i] = rmin[i + 1];
}
int max = 0;
for (int i = 0; i < rmin.length - 1; i++) {
if (max < nums[i])
max = nums[i];
if (max < rmin[i + 1])
return true;
}
return false;
}
}
```

` ````
Solution in Python :
class Solution:
def solve(self, nums):
n = len(nums)
right_mins = [math.inf] * n
for i, num in enumerate(reversed(nums)):
right_mins[~i] = min(num, right_mins[~i + 1])
left_max = -math.inf
for left_num, right_min in zip(nums, right_mins[1:]):
left_max = max(left_max, left_num)
if left_max < right_min:
return True
return False
```

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