Set - Google Top Interview Questions


Problem Statement :


Implement a set data structure with the following methods:

CustomSet() constructs a new instance of a set

add(int val) adds val to the set


exists(int val) returns whether val exists in the set

remove(int val) removes the val in the set

This should be implemented without using built-in set.


Constraints

n ≤ 100,000 where n is the number of calls to add, exists and remove

Example 1

Input

methods = ["constructor", "add", "exists", "remove", "exists"]

arguments = [[], [1], [1], [1], [1]]`

Output

[None, None, True, None, False]

Explanation

c = CustomSet()

c.add(1)

c.exists(1) == True

c.remove(1)

c.exists(1) == False



Solution :



title-img




                        Solution in C++ :

class CustomSet {
    int S = 1e3;
    vector<list<int>> v;
    hash<int> hs;

    public:
    CustomSet() {
        v.resize(S);
    }

    void add(int val) {
        if (exists(val)) return;
        int id = hs(val) % S;
        v[id].push_back(val);
    }

    bool exists(int val) {
        int id = hs(val) % S;
        for (int x : v[id]) {
            if (x == val) return true;
        }
        return false;
    }

    void remove(int val) {
        int id = hs(val) % S;
        for (auto it = v[id].begin(); it != v[id].end(); it++) {
            if (*it == val) {
                v[id].erase(it);
                return;
            }
        }
    }
};
                    


                        Solution in Java :

import java.util.*;

class CustomSet {
    ArrayList<Integer>[] buckets;
    int T;
    public CustomSet() {
        T = 300;

        buckets = new ArrayList[T];
    }

    public void add(int val) {
        if (!exists(val)) {
            buckets[map(val)].add(val);
        }
    }

    public boolean exists(int val) {
        int m = map(val);
        if (buckets[m] == null)
            buckets[m] = new ArrayList<Integer>();
        return buckets[m].contains(val);
    }

    public void remove(int val) {
        if (exists(val))
            buckets[map(val)].remove(Integer.valueOf(val));
    }

    public int map(int val) {
        return ((val % T) + T) % T;
    }
}
                    


                        Solution in Python : 
                            
class ListNode:
    def __init__(self, val):
        self.val = val
        self.next = None


class CustomSet:
    def __init__(self):
        self.mod = 2069  # any large prime number
        self.lst = [None] * self.mod

    def add(self, val):
        hashkey = val % self.mod
        if not self.lst[hashkey]:
            self.lst[hashkey] = ListNode(val)
        else:
            curr = self.lst[hashkey]
            while curr.next:
                if curr.val == val:
                    return
                curr = curr.next
            if curr.val == val:
                return
            curr.next = ListNode(val)

    def exists(self, val):
        hashkey = val % self.mod
        if self.lst[hashkey]:
            curr = self.lst[hashkey]
            while curr:
                if curr.val == val:
                    return True
                curr = curr.next
        return False

    def remove(self, val):
        hashkey = val % self.mod
        if self.lst[hashkey]:
            curr = self.lst[hashkey]
            if curr.val == val:
                self.lst[hashkey] = curr.next
                return
            while curr.next:
                if curr.next.val == val:
                    curr.next = curr.next.next
                    return
                curr = curr.next
                    


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