Search Insert Position


Problem Statement :


Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You must write an algorithm with O(log n) runtime complexity.

 

Example 1:

Input: nums = [1,3,5,6], target = 5
Output: 2
Example 2:

Input: nums = [1,3,5,6], target = 2
Output: 1
Example 3:

Input: nums = [1,3,5,6], target = 7
Output: 4
 

Constraints:

1 <= nums.length <= 104
-104 <= nums[i] <= 104
nums contains distinct values sorted in ascending order.
-104 <= target <= 104


Solution :



title-img 


                            Solution in C :

int searchInsert(int* nums, int numsSize, int target){
 int i;
    for (i = 0; i < numsSize  ; i++)
    {
        if (target<=nums[i])
        break;
        
    }
    return i;
        
}
                        


                        Solution in C++ :

class Solution {
public:
    int searchInsert(vector<int>& nums, int target) {
        int low=0;
        int high=nums.size();
        int mid;
        if(target>nums[high-1]){
            return high;
        }
        while(low<=high){
              mid=(low+high)/2;
            if(nums[mid]==target){  
                return mid;
            }
          
            if(target<nums[mid]){     
            high=mid-1;    
            }else{
            low=mid+1;        
            }
          
        }
         return  low;   
    }
};
                    


                        Solution in Java :

class Solution {
    public int searchInsert(int[] nums, int target) {
        int start = 0;
        int end = nums.length-1;

        while (start <= end) {
            int mid = start + (end-start)/2;
            if (nums[mid] == target) return mid;
            else if (nums[mid] > target) end = mid-1;
            else start = mid+1;
        }

        return start;
    }
}
                    


                        Solution in Python : 
                            
class Solution:
    def searchInsert(self, nums: List[int], target: int) -> int:
        nums.append(target)
        num = sorted(nums)
        index = num.index(target)
        return index


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