Rotate Image
Problem Statement :
You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise). You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation. Example 1: Input: matrix = [[1,2,3],[4,5,6],[7,8,9]] Output: [[7,4,1],[8,5,2],[9,6,3]] Example 2: Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]] Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]] Constraints: n == matrix.length == matrix[i].length 1 <= n <= 20 -1000 <= matrix[i][j] <= 1000
Solution :
Solution in C :
void rotate(int** a, int n, int* cn){
int x=0,i,t,y;n=n-1;
while(x<n){
y=n;
for(i=x;i<n;i++){
t=a[x][i];
a[x][i]=a[y][x];
a[y][x]=a[n][y];
a[n][y--]=a[i][n];
a[i][n]=t;
}
n--;
x++;
}
}
Solution in C++ :
class Solution {
public:
void rotate(vector<vector<int>>& matrix) {
int ro = matrix.size();
for(int i = 0 ;i< matrix.size()/2;i++){
for(int j = 0;j< matrix[i].size(); j++)
swap(matrix[i][j],matrix[ro-i-1][j]);
}
for(int i = 0; i< ro; i++){
cout<<i<<ro-i-1<<endl;
for(int j = i+1;j<ro ; j++){
cout<<"j"<<j<<endl;
swap(matrix[i][j], matrix[j][i]);
}
}
}
};
Solution in Java :
class Solution {
private void transpose(int[][] matrix) {
for(int i=0; i<matrix.length; i++) {
for(int j=i; j<matrix[0].length; j++) {
int temp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = temp;
}
}
}
private void reverseRows(int[][] matrix) {
for(int r=0; r<matrix.length; r++) {
int left = 0;
int right = matrix.length-1;
while(left < right) {
int temp = matrix[r][left];
matrix[r][left] = matrix[r][right];
matrix[r][right] = temp;
left++;
right--;
}
}
}
public void rotate(int[][] matrix) {
transpose(matrix);
reverseRows(matrix);
}
}
Solution in Python :
class Solution(object):
def rotate(self, matrix):
"""
:type matrix: List[List[int]]
:rtype: void Do not return anything, modify matrix in-place instead.
"""
half = (math.ceil(len(matrix) / 2))
r = None
if len(matrix) % 2 == 0:
r = range(half)
else:
r = range(half - 1)
for y in r:
for x in range(half):
tmp = matrix[y][x]
matrix[y][x] = matrix[-1 - x][y]
matrix[-1 - x][y] = matrix[-1 - y][-1 - x]
matrix[-1 - y][-1 - x] = matrix[x][-1 - y]
matrix[x][-1 -y] = tmp
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