**Largest K Sublist Sum - Amazon Top Interview Questions**

### Problem Statement :

You are given a list of integers nums, and an integer k, which represents a large list of nums concatenated k times. Return the sum of the sublist with the largest sum. The sublist can be empty. Constraints 0 ≤ n ≤ 100,000 where n is the length of nums. 0 ≤ k ≤ 10,000 Example 1 Input nums = [1, 3, 4, -5] k = 1 Output 8 Explanation We can take the sublist [1, 3, 4] Example 2 Input nums = [1, 3, 4, -5] k = 2 Output 11 Explanation We can take the sublist [1, 3, 4, -5, 1, 3, 4]

### Solution :

` ````
Solution in C++ :
int solve(vector<int>& nums, int k) {
int cs = accumulate(nums.begin(), nums.end(), 0), rs = 0, ans = 0, n = nums.size();
for (int i = 0; i < 2 * n; i++) {
if (k == 0 or (k == 1 and i >= n)) break;
if (i == n) rs += max(0, (k - 2) * cs);
rs = max({0, rs + nums[i % n], nums[i % n]});
ans = max(ans, rs);
}
return ans;
}
```

` ````
Solution in Python :
class Solution:
def solve(self, nums, k):
cur = ans = 0
for _ in range(min(k, 2)):
for a in nums:
cur = max(a, cur + a)
ans = max(ans, cur)
return ans + max(0, sum(nums)) * max(0, k - 2)
```

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