Create Largest Number From a List - Amazon Top Interview Questions
Problem Statement :
Given a list of integers nums, rearrange its order to form the largest possible integer and return it as a string. Constraints n ≤ 1,000 where n is the length of nums nums[i] ≤ 1,000 Example 1 Input nums = [10, 7, 76, 415] Output "77641510" Example 2 Input nums = [961, 745, 331, 794, 923] Output "961923794745331" Example 3 Input nums = [45, 14, 70, 67, 95] Output "9570674514" Example 4 Input nums = [70, 5, 94, 18, 78] Output "947870518"
Solution :
Solution in C++ :
string solve(vector<int>& _nums) {
// if i have two numbers
// i can try both the ways to combine them
// and select the larger way!
vector<string> nums;
for (const int& num : _nums) {
nums.push_back(to_string(num));
}
// now i just sort these to give the biggest value
sort(nums.begin(), nums.end(), [](const string& a, const string& b) {
string ab = a + b, ba = b + a;
return ab > ba;
});
string res = "";
for (const string& num : nums) {
res += num;
}
return res;
}
Solution in Java :
import java.util.*;
import java.util.stream.Collectors;
class Solution {
public String solve(int[] nums) {
return Arrays.stream(nums)
.mapToObj(String::valueOf)
.sorted(Collections.reverseOrder((s1, s2) -> (s1 + s2).compareTo(s2 + s1)))
.collect(Collectors.joining());
}
}
Solution in Python :
class Number:
def __init__(self, n):
self.n = str(n)
def __lt__(self, other):
return self.n + other.n > other.n + self.n
def __str__(self):
return self.n
class Solution:
def solve(self, nums):
return ''.join(map(str, sorted(map(Number, nums))))
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