Brick Layout - Google Top Interview Questions

Problem Statement :

You are given a list of integers bricks and integers width and height. 
Each bricks[i] represents a 1 x bricks[i] size brick. 
Return the number of ways to lay the bricks such that we get full layout of bricks with width width and height height. Bricks can be reused but can only be laid horizontally.

Answer fits within 32-bit integer.


1 ≤ n ≤ 1,000 where n is the length of bricks

1 ≤ width * n ≤ 100,000

Example 1


bricks = [2, 3]

width = 5

height = 2




We can lay the first row of bricks with [2, 3] or [3, 2] and we can lay the second row of bricks with [2, 3] 
or [3, 2].

Example 2


bricks = [2, 2]

width = 2

height = 1



Solution :


                        Solution in C++ :

int solve(vector<int>& nums, int w, int h) {
    vector<int> dp(w + 1);
    dp[0] = 1;

    for (int i = 1; i <= w; ++i) {
        for (const auto& num : nums) {
            if (num <= i) dp[i] += dp[i - num];

    return pow(dp[w], h);

                        Solution in Python : 
class Solution:
    def solve(self, bricks, width, height):
        w = [1] + [0] * width
        for i in range(width):
            if w[i]:
                for x in bricks:
                    if i + x <= width:
                        w[i + x] += w[i]
        return w[width] ** height

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