# Brick Layout - Google Top Interview Questions

### Problem Statement :

```You are given a list of integers bricks and integers width and height.
Each bricks[i] represents a 1 x bricks[i] size brick.
Return the number of ways to lay the bricks such that we get full layout of bricks with width width and height height. Bricks can be reused but can only be laid horizontally.

Constraints

1 ≤ n ≤ 1,000 where n is the length of bricks

1 ≤ width * n ≤ 100,000

Example 1

Input

bricks = [2, 3]

width = 5

height = 2

Output

4

Explanation

We can lay the first row of bricks with [2, 3] or [3, 2] and we can lay the second row of bricks with [2, 3]
or [3, 2].

Example 2

Input

bricks = [2, 2]

width = 2

height = 1

Output

2```

### Solution :

```                        ```Solution in C++ :

int solve(vector<int>& nums, int w, int h) {
vector<int> dp(w + 1);
dp = 1;

for (int i = 1; i <= w; ++i) {
for (const auto& num : nums) {
if (num <= i) dp[i] += dp[i - num];
}
}

return pow(dp[w], h);
}```
```

```                        ```Solution in Python :

class Solution:
def solve(self, bricks, width, height):
w =  +  * width
for i in range(width):
if w[i]:
for x in bricks:
if i + x <= width:
w[i + x] += w[i]
return w[width] ** height```
```

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