**Array Reversal**

### Problem Statement :

Given an array, of size n, reverse it. Example: If array, arr=[1.2.3.4,5] after reversing it, the array should be, arr=[5,4,3,2,1] Input Format: The first line contains an integer, n, denoting the size of the array. The next line contains n space-separated integers denoting the elements of the array. Constraints: 1<=n<=1000 1<=arr[i]<=1000, where is the element of the array. Output Format: The output is handled by the code given in the editor, which would print the array.

### Solution :

` ````
Solution in C :
#include <stdio.h>
#include <stdlib.h>
int main()
{
int num, *arr, i;
scanf("%d", &num);
arr = (int*) malloc(num * sizeof(int));
for(i = 0; i < num; i++) {
scanf("%d", arr + i);
}
for(i = num-1; i>-1; i--)
printf("%d ", *(arr + i));
return 0;
}
```

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