Check Strict Superset Python
You are given a set A and n other sets. Your job is to find whether set A is a strict superset of each of the N sets. Print True, if A is a strict superset of each of the N sets. Otherwise, print False. A strict superset has at least one element that does not exist in its subset. Example Set ([1,3,4]) is a strict superset of set ([1,3]). Set ([1,3,4]) is not a strict superset of set ([1,3,4]). Set ([1,3,4]) is not a strict superset of set ([1,3,5]). Input Format The first li
View Solution →itertools.product() python
itertools.product() This tool computes the cartesian product of input iterables. It is equivalent to nested for-loops. For example, product(A, B) returns the same as ((x,y) for x in A for y in B). Sample Code >>> from itertools import product >>> >>> print list(product([1,2,3],repeat = 2)) [(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (3, 3)] >>> >>> print list(product([1,2,3],[3,4])) [(1, 3), (1, 4), (2, 3), (2, 4), (3, 3), (3, 4)] >>> >>> A = [[1,2,3],[3,4
View Solution →itertools.permutations() python
itertools.permutations(iterable[, r]) This tool returns successive r length permutations of elements in an iterable. If r is not specified or is None, then r defaults to the length of the iterable, and all possible full length permutations are generated. Permutations are printed in a lexicographic sorted order. So, if the input iterable is sorted, the permutation tuples will be produced in a sorted order. Sample Code >>> from itertools import permutations >>> print permutations([
View Solution →itertools.combinations() python
itertools.combinations(iterable, r) This tool returns the r length subsequences of elements from the input iterable. Combinations are emitted in lexicographic sorted order. So, if the input iterable is sorted, the combination tuples will be produced in sorted order. Sample Code >>> from itertools import combinations >>> >>> print list(combinations('12345',2)) [('1', '2'), ('1', '3'), ('1', '4'), ('1', '5'), ('2', '3'), ('2', '4'), ('2', '5'), ('3', '4'), ('3', '5'), ('4', '5')] >>
View Solution →itertools.combinations_with_replacement() python
itertools.combinations_with_replacement(iterable, r) This tool returns r length subsequences of elements from the input iterable allowing individual elements to be repeated more than once. Combinations are emitted in lexicographic sorted order. So, if the input iterable is sorted, the combination tuples will be produced in sorted order. Sample Code >>> from itertools import combinations_with_replacement >>> >>> print list(combinations_with_replacement('12345',2)) [('1', '1'), ('1',
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