Vector-Sort C++


Problem Statement :


You are given integers N .Sort N the integers and print the sorted order.
Store the N integers in a vector.Vectors are sequence containers representing arrays that can change in size.

    Declaration:

    vector<int>v; (creates an empty vector of integers)

    Size:

    int size=v.size();

    Pushing an integer into a vector:

    v.push_back(x);(where x is an integer.The size increases by 1 after this.)

    Popping the last element from the vector:

    v.pop_back(); (After this the size decreases by 1)

    Sorting a vector:

    sort(v.begin(),v.end()); (Will sort all the elements in the vector)

To know more about vectors, Click Here

Input Format

The first line of the input contains N where N is the number of integers. The next line contains N integers.

Constraints

  1 <= N  <= 10^5
  1 <= Vi  <= 10^9 , where Vi is the ith integer in the vector.

Output Format

Print the integers in the sorted order one by one in a single line followed by a space.


Solution :



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                            Solution in C :

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
    int N = 0;
    cin>>N;
    
    vector<int> vecInt;
    int number = 0;
    
    while (cin>>number)
        vecInt.push_back(number);
    
    sort(vecInt.begin(), vecInt.end());
    
    for ( vector<int>::iterator it = vecInt.begin(); it != vecInt.end(); it++)
        cout<<*it<<" ";
    return 0;
}








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