# Time Conversion

### Problem Statement :

```Given a time in 12 -hour AM/PM format, convert it to military (24-hour) time.

Note: - 12:00:00AM on a 12-hour clock is 00:00:00 on a 24-hour clock.
- 12:00:00PM on a 12-hour clock is 12:00:00 on a 24-hour clock.

Example
s = '12 : 01: 00PM'
Return '12:01:00'.

s = '12 : 01: 00AM'
Return '00:01:00'.

Function Description

Complete the timeConversion function in the editor below. It should return a new string representing the input time in 24 hour format.

timeConversion has the following parameter(s):

string s: a time in 12 hour format

Input Format

A single string s that represents a time in 12 -hour clock format (i.e.: hh:mm:ss AM or hh:mm:ss PM)

Constraints

All input times are valid```

### Solution :

```                            ```Solution in C :

In C :

char* timeConversion(char* s) {
char test;
static char final;
final = s;
final = s;
final = ':';
final = ':';
final = s;
final = s;
final = s;
final = s;

if(s == 'A')
{
if(s=='1' && s=='2')
{
final = '0';
final = '0';
}
else{
final = s;
final = s;
}
}

else if(s== 'P')
{
if(s == '0' && s < '8')
{
final = '1';
char hr = (int)s;
hr = hr+2;
final  = (char)hr;
}
else if(s == '0' && (s == '8' || s == '9'))
{
final = '2';
if(s == '8') final = '0';
else final = '1';

}
else if(s != '0' && (s == '0' || s == '1'))
{   final = '2';
if(s == '0') final = '2';
else if(s == '1')  final = '3';
}

}//end of PM if

return final;
}

In Java :

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String s = sc.nextLine(); //07:05:45PM
DateFormat inFormat = new SimpleDateFormat( "hh:mm:ssaa");
DateFormat outFormat = new SimpleDateFormat( "HH:mm:ss");

Date date = null;
try {
date = inFormat.parse(s);
}catch (ParseException e ){
e.printStackTrace();
}
if( date != null ){
String myDate = outFormat.format(date);
System.out.println(myDate);
}
}

}

In Python3 :

ins = input().strip()

is_pm = ins[-2:].lower() == 'pm'
time_list = list(map(int, ins[:-2].split(':')))

if is_pm and time_list < 12:
time_list += 12

if not is_pm and time_list == 12:
time_list = 0

print(':'.join(map(lambda x: str(x).rjust(2, '0'), time_list)))

In C ++ :

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

int main() {

string s;
string h;
int hr;
cin>>s;
hr = ((s-'0')*10)+(s-'0');
if(s=='P'&&s=='M'&& hr ==12) cout<<to_string(hr);
else if(s=='P'&&s=='M') cout<<to_string(hr+12);
else if(s=='A'&&s=='M'&&hr==12) cout<<"00";

else cout<< s<<s;

for(int i =2;i<8;i++)
cout<<s[i];
cout<<endl;
return 0;
}```
```

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