Time Conversion


Problem Statement :


Given a time in 12 -hour AM/PM format, convert it to military (24-hour) time.

Note: - 12:00:00AM on a 12-hour clock is 00:00:00 on a 24-hour clock.
- 12:00:00PM on a 12-hour clock is 12:00:00 on a 24-hour clock.

Example 
s = '12 : 01: 00PM'
   Return '12:01:00'.

s = '12 : 01: 00AM'
  Return '00:01:00'.


Function Description

Complete the timeConversion function in the editor below. It should return a new string representing the input time in 24 hour format.

timeConversion has the following parameter(s):

    string s: a time in 12 hour format 

Input Format

A single string s that represents a time in 12 -hour clock format (i.e.: hh:mm:ss AM or hh:mm:ss PM)

Constraints

    All input times are valid


Solution :



title-img


                            Solution in C :

In C :

char* timeConversion(char* s) {
    char test[2];
    static char final[9];
final[0] = s[0];
final[1] = s[1];
final[2] = ':';
final[5] = ':';
final[3] = s[3];
final[4] = s[4];
final[6] = s[6];
final[7] = s[7];
   
    if(s[8] == 'A')
    {
        if(s[0]=='1' && s[1]=='2')
        {
            final[0] = '0';
            final[1] = '0';
        }
        else{
            final[0] = s[0];
            final[1] = s[1];
        }
    }


    else if(s[8]== 'P')
    {
       if(s[0] == '0' && s[1] < '8')
       {
           final[0] = '1';
           char hr = (int)s[1];
           hr = hr+2;
           final[1]  = (char)hr;
       }
       else if(s[0] == '0' && (s[1] == '8' || s[1] == '9'))
       {
           final[0] = '2';
          if(s[2] == '8') final[1] = '0';
          else final[1] = '1';
          
       }
       else if(s[0] != '0' && (s[1] == '0' || s[1] == '1'))
       {   final[0] = '2';
           if(s[1] == '0') final[1] = '2';
           else if(s[1] == '1')  final[1] = '3';
       }
    
    }//end of PM if

    

return final;
}





In Java :


import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

   	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		String s = sc.nextLine(); //07:05:45PM
		DateFormat inFormat = new SimpleDateFormat( "hh:mm:ssaa");
		DateFormat outFormat = new SimpleDateFormat( "HH:mm:ss");

		Date date = null;
		try {
			date = inFormat.parse(s); 
		}catch (ParseException e ){
			e.printStackTrace();
		}
		if( date != null ){
			String myDate = outFormat.format(date);
			System.out.println(myDate);
		}
	}

}





In Python3 :


ins = input().strip()

is_pm = ins[-2:].lower() == 'pm'
time_list = list(map(int, ins[:-2].split(':')))

if is_pm and time_list[0] < 12:
    time_list[0] += 12

if not is_pm and time_list[0] == 12:
    time_list[0] = 0

print(':'.join(map(lambda x: str(x).rjust(2, '0'), time_list)))





In C ++ :


#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;


int main() {
   
    string s;
    string h;
    int hr;
    cin>>s;
    hr = ((s[0]-'0')*10)+(s[1]-'0');
    if(s[8]=='P'&&s[9]=='M'&& hr ==12) cout<<to_string(hr);
    else if(s[8]=='P'&&s[9]=='M') cout<<to_string(hr+12);
    else if(s[8]=='A'&&s[9]=='M'&&hr==12) cout<<"00";
    
    else cout<< s[0]<<s[1];
    
   
    for(int i =2;i<8;i++)
        cout<<s[i];
    cout<<endl;
    return 0;
}
                        




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