**The Accountant - Google Top Interview Questions**

### Problem Statement :

Spreadsheets often use this alphabetical encoding for its columns: "A", "B", "C", ..., "AA", "AB", "AC", ..., "ZZ", "AAA", "AAB", "AAC", .... Given a column number n, return its alphabetical column id. For example, given 1, return "A". Given 27, return "AA". Constraints 1 ≤ n < 2 ** 31 Example 1 Input n = 1 Output "A" Example 2 Input n = 2 Output "B" Example 3 Input n = 26 Output "Z" Example 4 Input n = 27 Output "AA"

### Solution :

` ````
Solution in C++ :
string solve(int n) {
string result;
while (n > 0) {
// Since in code 'A' + 25 = 'Z'
n--;
// Get the remainder to identify
// the current character to be
// added to the column number
int curr = n % 26;
// Divide by 26 to process the
// next character
n = n / 26;
// Update the result with the
// current character
result.push_back(curr + 'A');
}
// Since we are adding the most
// significant character to the end
// of the string, reverse it before
// returning
reverse(result.begin(), result.end());
return result;
}
```

` ````
Solution in Java :
import java.util.*;
class Solution {
public String solve(int A) {
String s = "";
int counter = 0;
while (A > 0) {
counter = (A - 1) % 26;
char a = (char) ('A' + counter);
s = a + s;
A = (A - 1) / 26;
}
return s;
}
}
```

` ````
Solution in Python :
class Solution:
def solve(self, n):
ans = ""
# because we have 1 based indexing
# we need to scale 1-27 to 0-26 each time
# so, we use n-1
while n >= 1:
ans += chr((n - 1) % 26 + ord("A"))
n = (n - 1) // 26
return ans[::-1]
```

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