**Swappable Trees - Amazon Top Interview Questions**

### Problem Statement :

Given two trees root0 and root1, return whether you can transform root0 into root1 by swapping any node's left and right subtrees any number of times. Example 1 Input root0 = [1, [3, null, null], [4, [0, null, [2, null, null]], null]] root1 = [1, [3, null, null], [4, [0, null, [2, null, null]], null]] Output True

### Solution :

` ````
Solution in C++ :
bool solve(Tree* root0, Tree* root1) {
if (!root0 and !root1) return true;
if (!root0 or !root1 or root0->val != root1->val) return false;
return (solve(root0->left, root1->left) and solve(root0->right, root1->right)) or
(solve(root0->right, root1->left) and solve(root0->left, root1->right));
}
```

` ````
Solution in Python :
class Solution:
def solve(self, source, target):
if not source or not target:
return not source and not target
t = self.isSubtree(target, source)
return t
def isSubtree(self, s, t):
if not s:
return False
elif self.sametree(s, t):
return True
else:
return self.isSubtree(s.right, t) or self.isSubtree(s.left, t)
def sametree(self, s, t):
if not s or not t:
return not s and not t
elif s.val == t.val:
return (self.sametree(s.left, t.left) and self.sametree(s.right, t.right)) or (
self.sametree(s.right, t.left) and self.sametree(s.left, t.right)
)
else:
return False
```

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