Subarray Division

                            Solution in C :

python3  :

n = int(input())
s = list(map(int, input().split()))
d, m = map(int, input().split())

ans = 0
for i in range(n-m+1):
    if (sum(s[i:i+m]) == d):
        ans += 1
        
print(ans)








Java  :

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int[] squares = new int[n];
        for(int squares_i=0; squares_i < n; squares_i++){
            squares[squares_i] = in.nextInt();
        }
        int d = in.nextInt();
        int m = in.nextInt();
        int result = 0;
        
        for(int i = 0; i < n-m+1; i++){
            int tmpSum = 0;
            for(int j = i; j < i+m; j++){
                tmpSum+= squares[j];
            } 
            if(tmpSum == d){
                result++;
            }
        }
        System.out.println(result);
        
    }
}







C ++  :

#include<bits/stdc++.h>
#define mp make_pair
#define pb push_back
#define ll long long
using namespace std;
int n,d,m,a[105],s[105],ans;
int main(){

    cin>>n;
    for(int i=1;i<=n;i++){
        cin>>a[i];
        s[i]=s[i-1]+a[i];
    }
    cin>>d>>m;

    for(int i=m;i<=n;i++)
        if(s[i]-s[i-m]==d)
            ans++;
    cout<<ans<<endl;

    return 0;
}








C  :

#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int main(){
    int n; 
    scanf("%d",&n);
    int *squares = malloc(sizeof(int) * n);
    for(int squares_i = 0; squares_i < n; squares_i++){
       scanf("%d",&squares[squares_i]);
    }
    int d; 
    int m; 
    scanf("%d %d",&d,&m);
    int count = 0;
    for (int i = 0; i <= n-m; ++i){
        int sum = 0;
        for (int j = i; j < i+m; ++j){
            sum += squares[j];
        }
        if (sum == d) ++count;
    }
    printf("%d", count);
    return 0;
}