Structuring the Document C
Problem Statement :
A document is represented as a collection paragraphs, a paragraph is represented as a collection of sentences, a sentence is represented as a collection of words and a word is represented as a collection of lower-case ([a-z]) and upper-case ([A-Z]) English characters. You will convert a raw text document into its component paragraphs, sentences and words. To test your results, queries will ask you to return a specific paragraph, sentence or word as described below. Alicia is studying the C programming language at the University of Dunkirk and she represents the words, sentences, paragraphs, and documents using pointers: A word is described by char * . A sentence is described by char ** . The words in the sentence are separated by one space (" "). The last word does not end with a space(" "). A paragraph is described by char *** . The sentences in the paragraph are separated by one period ("."). A document is described by char **** . The paragraphs in the document are separated by one newline("\n"). The last paragraph does not end with a newline. For example: Learning C is fun. Learning pointers is more fun.It is good to have pointers. The only sentence in the first paragraph could be represented as: char** first_sentence_in_first_paragraph = {"Learning", "C", "is", "fun"}; The first paragraph itself could be represented as: char*** first_paragraph = {{"Learning", "C", "is", "fun"}}; The first sentence in the second paragraph could be represented as: char** first_sentence_in_second_paragraph = {"Learning", "pointers", "is", "more", "fun"}; The second sentence in the second paragraph could be represented as: char** second_sentence_in_second_paragraph = {"It", "is", "good", "to", "have", "pointers"}; The second paragraph could be represented as: char*** second_paragraph = {{"Learning", "pointers", "is", "more", "fun"}, {"It", "is", "good", "to", "have", "pointers"}}; Finally, the document could be represented as: char**** document = {{{"Learning", "C", "is", "fun"}}, {{"Learning", "pointers", "is", "more", "fun"}, {"It", "is", "good", "to", "have", "pointers"}}}; The first line contains the integer paragraph_count. Each of the next paragraph_count lines contains a paragraph as a single string. The next line contains the integer q, the number of queries. Each of the next q lines or groups of lines contains a query in one of the following formats: 1 The first line contains 1 k : The next line contains an integer x , the number of sentences in the kth paragraph. Each of the next x lines contains an integer a[i], the number of words in the ith sentence. This query corresponds to calling the function kth_paragraph. 2 The first line contains 2 k m: The next line contains an integer x , the number of words in the kth sentence of the mth paragraph. This query corresponds to calling the function kth_sentence_in_mth_paragraph. 3 The only line contains 3 k m n: This query corresponds to calling the function kth_word_in_mth_sentence_of_nth_paragraph. Constraints The text which is passed to the get_document has words separated by a space (" "), sentences separated by a period (".") and paragraphs separated by a newline("\n"). The last word in a sentence does not end with a space. The last paragraph does not end with a newline. The words contain only upper-case and lower-case English letters. 1 <= number of characters in the entire document <= 1000 1 <= number of paragraphs in the entire document <= 5 Output Format Print the paragraph, sentence or the word corresponding to the query to check the logic of your code.
Solution :
Solution in C :
char* kth_word_in_mth_sentence_of_nth_paragraph(char**** document, int k, int m, int n) {
return document[n-1][m-1][k-1];
}
char** kth_sentence_in_mth_paragraph(char**** document, int k, int m) {
return document[m-1][k-1];
}
char*** kth_paragraph(char**** document, int k) {
return document[k-1];
}
char** split_string(char* text, char delim) {
assert(text != NULL);
char** result = malloc(1*sizeof(char*));
int size = 1;
char* temp = strtok(text, &delim);
*result = temp;
while(temp != NULL) {
size++;
result = realloc(result,size*sizeof(char*));
temp = strtok(NULL, &delim);
result[size-1] = temp;
}
return result;
}
char**** get_document(char* text) {
assert(text != NULL);
// split text by '\n' and count number of paragraphs
char** paragraphs = split_string(text, '\n');
int npar = 0;
while (paragraphs[npar] != NULL) {
npar++;
}
char**** doc = malloc((npar+1)*sizeof(char***));
// set last position to NULL for the user
// to know when the array ends.
doc[npar] = NULL;
int i = 0;
while (paragraphs[i] != NULL) {
// split sentences of paragraph by '.' and count number of sentences
char** sentences = split_string(paragraphs[i], '.');
int nsen = 0;
while(sentences[nsen] != NULL) {
nsen++;
}
doc[i] = malloc((nsen+1)*sizeof(char**));
// set last position to NULL for the user
// to know when the array ends.
doc[i][nsen] = NULL;
int j = 0;
while (sentences[j] != NULL) {
// remember that doc[0][0] means: paragraph #0,
// sentence #0 and should act like a pointer to
// the first element of an array of words (strings)
// split string by ' ' and associate doc[i][j]
// with the array of strings representing words
// that is returned by split_string.
doc[i][j] = split_string(sentences[j], ' ');
j++;
}
i++;
}
return doc;
}
View More Similar Problems
Insert a Node at the Tail of a Linked List
You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Input Format: You have to complete the SinglyLink
View Solution →Insert a Node at the head of a Linked List
Given a pointer to the head of a linked list, insert a new node before the head. The next value in the new node should point to head and the data value should be replaced with a given value. Return a reference to the new head of the list. The head pointer given may be null meaning that the initial list is empty. Function Description: Complete the function insertNodeAtHead in the editor below
View Solution →Insert a node at a specific position in a linked list
Given the pointer to the head node of a linked list and an integer to insert at a certain position, create a new node with the given integer as its data attribute, insert this node at the desired position and return the head node. A position of 0 indicates head, a position of 1 indicates one node away from the head and so on. The head pointer given may be null meaning that the initial list is e
View Solution →Delete a Node
Delete the node at a given position in a linked list and return a reference to the head node. The head is at position 0. The list may be empty after you delete the node. In that case, return a null value. Example: list=0->1->2->3 position=2 After removing the node at position 2, list'= 0->1->-3. Function Description: Complete the deleteNode function in the editor below. deleteNo
View Solution →Print in Reverse
Given a pointer to the head of a singly-linked list, print each data value from the reversed list. If the given list is empty, do not print anything. Example head* refers to the linked list with data values 1->2->3->Null Print the following: 3 2 1 Function Description: Complete the reversePrint function in the editor below. reversePrint has the following parameters: Sing
View Solution →Reverse a linked list
Given the pointer to the head node of a linked list, change the next pointers of the nodes so that their order is reversed. The head pointer given may be null meaning that the initial list is empty. Example: head references the list 1->2->3->Null. Manipulate the next pointers of each node in place and return head, now referencing the head of the list 3->2->1->Null. Function Descriptio
View Solution →