# String Construction

### Problem Statement :

```Amanda has a string of lowercase letters that she wants to copy to a new string. She can perform the following operations with the given costs. She can perform them any number of times to construct a new string :

Append a character to the end of string  at a cost of  dollar.
Choose any substring of  and append it to the end of  at no charge.
Given  strings , find and print the minimum cost of copying each  to  on a new line.

For example, given a string , it can be copied for  dollars. Start by copying ,  and  individually at a cost of  dollar per character. String  at this time. Copy  to the end of  at no cost to complete the copy.

Function Description

Complete the stringConstruction function in the editor below. It should return the minimum cost of copying a string.

stringConstruction has the following parameter(s):

s: a string
Input Format

The first line contains a single integer n, the number of strings
Each of the next  lines contains a single string, .s[ i ].

Constraints

1  <=   n  <=  5
1  <=  | S[ i ] |  <= 10^5

Output Format

For each string s[ i ] print the minimum cost of constructing a new string p [ i ]  on a new line.```

### Solution :

```                            ```Solution in C :

In   C++  :

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
#include<bits/stdc++.h>
using namespace std;

int main() {

int n;
cin>>n;
for(int i=0;i<n;i++){
string s;
cin>>s;
set<char> a;
for(int i=0;i<s.size();i++){
a.insert(s[i]);
}
cout<<a.size()<<endl;
}
return 0;
}

In   Java  :

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
for(int a0 = 0; a0 < n; a0++){
String s = in.next();
HashSet<Character> hs=new HashSet<Character>();
int count=0;
for(int i=0;i<s.length();i++){
if(!hs.contains(s.charAt(i))){
count++;
}
}
System.out.println(count);
}

}
}

In  C  :

#include <stdio.h>
#include <string.h>

int main(void) {

int t;scanf("%d",&t);
while(t--)
{	char inp;
int i,c=0,l,arr;
for(i=0;i<26;i++)arr[i]=0;
scanf("%s",inp);
l=strlen(inp);
for(i=0;i<l;i++)
{
arr[inp[i]-'a']+=1;
}
for(i=0;i<26;i++)
if(arr[i]!=0)
c+=1;
printf("%d\n",c);}
return 0;
}

In  Python3 :

t = int(input())

for i in range(t):
s = input()
print(len(set(s)))```
```

## Insert a node at a specific position in a linked list

Given the pointer to the head node of a linked list and an integer to insert at a certain position, create a new node with the given integer as its data attribute, insert this node at the desired position and return the head node. A position of 0 indicates head, a position of 1 indicates one node away from the head and so on. The head pointer given may be null meaning that the initial list is e

## Delete a Node

Delete the node at a given position in a linked list and return a reference to the head node. The head is at position 0. The list may be empty after you delete the node. In that case, return a null value. Example: list=0->1->2->3 position=2 After removing the node at position 2, list'= 0->1->-3. Function Description: Complete the deleteNode function in the editor below. deleteNo

## Print in Reverse

Given a pointer to the head of a singly-linked list, print each data value from the reversed list. If the given list is empty, do not print anything. Example head* refers to the linked list with data values 1->2->3->Null Print the following: 3 2 1 Function Description: Complete the reversePrint function in the editor below. reversePrint has the following parameters: Sing