**Split List to Minimize Largest Sum - Amazon Top Interview Questions**

### Problem Statement :

Given a list of non-negative integers nums and an integer k, you can split the list into k non-empty sublists. Return the minimum largest sum of the k sublists. Constraints k ≤ n ≤ 100,000 where n is the length of nums Example 1 Input nums = [1, 3, 2, 4, 9] k = 2 Output 10 Explanation We can split the list into these 2 sublists: [1, 3, 2, 4] and [9].

### Solution :

` ````
Solution in C++ :
int sublistCount(vector<int>& nums, long long threshold) {
int ret = 1;
long long leftover = threshold;
for (int val : nums) {
if (val > leftover) {
ret++;
leftover = threshold;
}
leftover -= val;
}
return ret;
}
int solve(vector<int>& nums, int k) {
long long lhs = *max_element(nums.begin(), nums.end());
long long rhs = accumulate(nums.begin(), nums.end(), 0LL);
while (lhs < rhs) {
long long mid = (lhs + rhs) / 2;
if (sublistCount(nums, mid) <= k)
rhs = mid;
else
lhs = mid + 1;
}
return lhs;
}
```

` ````
Solution in Java :
import java.util.*;
class Solution {
public int solve(int[] nums, int k) {
int max = 0, sum = 0;
for (int i : nums) {
max = Math.max(i, max);
sum += i;
}
int l = max, h = sum;
while (l <= h) {
int m = (l + h) >>> 1;
if (can(nums, m, k))
h = m - 1;
else
l = m + 1;
}
return l;
}
private boolean can(int[] nums, final int MAX, final int K) {
int groups = 0, sum = -1;
for (int i : nums) {
if (sum + i > MAX)
sum = -1;
if (sum == -1) {
groups++;
sum = 0;
}
sum += i;
}
return groups <= K;
}
}
```

` ````
Solution in Python :
def parse(x):
i = 0
cnt = 0 # counts the number of sublists
while i < n:
tempX = x
while i < n and tempX - nums[i] >= 0:
tempX -= nums[i]
i += 1
cnt +=1
return cnt <= k
```

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