# Number Line Jumps

### Problem Statement :

```You are choreographing a circus show with various animals. For one act, you are given two kangaroos on a number line ready to jump in the positive direction (i.e, toward positive infinity).

The first kangaroo starts at location x1 and moves at a rate of v1 meters per jump.
The second kangaroo starts at location x2 and moves at a rate of v2 meters per jump.
You have to figure out a way to get both kangaroos at the same location at the same time as part of the show. If it is possible, return YES, otherwise return NO.

For example, kangaroo 1 starts at x1=2 with a jump distance v1=1 and kangaroo 2 starts at x2=1 with a jump distance of v2=2. After one jump, they are both at x=3, (x1+v1 = 2+1, x2+v2 = 1+2 ), so our answer is YES.

Function Description

Complete the function kangaroo in the editor below. It should return YES if they reach the same position at the same time, or NO if they don't.

kangaroo has the following parameter(s):

x1, v1: integers, starting position and jump distance for kangaroo 1
x2, v2: integers, starting position and jump distance for kangaroo 2
Input Format

A single line of four space-separated integers denoting the respective values of x1, v1, x2, and v2.

Constraints
0 <= x1, x2 <= 10000
1 <= v1 <= 10000
1 <= v2 <= 10000

Output Format

Print YES if they can land on the same location at the same time; otherwise, print NO.

Note: The two kangaroos must land at the same location after making the same number of jumps.```

### Solution :

```                            ```Solution in C :

c   :

#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int main(){
int x1;
int v1;
int x2;
int v2;
scanf("%d %d %d %d",&x1,&v1,&x2,&v2);
if(x2>x1){
if(v2<v1){
if((x2-x1)%(v1-v2)==0)
printf("YES");
else
printf("NO");
}
else
printf("NO");
}
else{
if(v1>v2){
if((x1-x2)%(v2-v1)==0)
printf("YES");
else
printf("NO");
}
else if(x1==x2&&v1==v2)
printf("YES");
else
printf("NO");
}
return 0;
}

C++ :

#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <bitset>
#include <cstdio>
#include <limits>
#include <vector>
#include <climits>
#include <cstring>
#include <cstdlib>
#include <fstream>
#include <numeric>
#include <sstream>
#include <iostream>
#include <algorithm>
#include <unordered_map>

using namespace std;

int main(){
int x1;
int v1;
int x2;
int v2;
cin >> x1 >> v1 >> x2 >> v2;
if ((v1 <= v2) || ((x2 - x1) % (v2 - v1))) {
puts("NO");
} else {
puts("YES");
}
return 0;
}

Java   :

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int x1 = in.nextInt();
int v1 = in.nextInt();
int x2 = in.nextInt();
int v2 = in.nextInt();
if(x1>x2)
{
if(v1<v2)
{
for(;;)
{
x1=x1+v1;
x2=x2+v2;
if (x1==x2)
{
System.out.println("YES");
break;
}
else
{
if (x2>x1)
{
System.out.println("NO");
break;
}
}
}
}
else
System.out.println("NO");

}
else if(x1<x2)
{
if(v1>v2)
{
for(;;)
{
x1=x1+v1;
x2=x2+v2;
if (x1==x2)
{
System.out.println("YES");
break;
}
else
{
if (x1>x2)
{
System.out.println("NO");
break;
}
}
}
}
else
System.out.println("NO");
}
else
{
if(v1==v2)
System.out.println("YES");
else
System.out.println("NO");
}
}
}

python3  :

a, b, c, d = map(int, input().split(' '))
if a-c==0:
print("YES")
quit()
if d-b==0:
print("NO")
quit()
if ((a-c)%(d-b)==0 and (a-c)//(d-b)>=0):
print("YES")
quit()
print("NO")```
```

## Equal Stacks

ou have three stacks of cylinders where each cylinder has the same diameter, but they may vary in height. You can change the height of a stack by removing and discarding its topmost cylinder any number of times. Find the maximum possible height of the stacks such that all of the stacks are exactly the same height. This means you must remove zero or more cylinders from the top of zero or more of

## Game of Two Stacks

Alexa has two stacks of non-negative integers, stack A = [a0, a1, . . . , an-1 ] and stack B = [b0, b1, . . . , b m-1] where index 0 denotes the top of the stack. Alexa challenges Nick to play the following game: In each move, Nick can remove one integer from the top of either stack A or stack B. Nick keeps a running sum of the integers he removes from the two stacks. Nick is disqualified f

## Largest Rectangle

Skyline Real Estate Developers is planning to demolish a number of old, unoccupied buildings and construct a shopping mall in their place. Your task is to find the largest solid area in which the mall can be constructed. There are a number of buildings in a certain two-dimensional landscape. Each building has a height, given by . If you join adjacent buildings, they will form a solid rectangle

## Simple Text Editor

In this challenge, you must implement a simple text editor. Initially, your editor contains an empty string, S. You must perform Q operations of the following 4 types: 1. append(W) - Append W string to the end of S. 2 . delete( k ) - Delete the last k characters of S. 3 .print( k ) - Print the kth character of S. 4 . undo( ) - Undo the last (not previously undone) operation of type 1 or 2,

## Poisonous Plants

There are a number of plants in a garden. Each of the plants has been treated with some amount of pesticide. After each day, if any plant has more pesticide than the plant on its left, being weaker than the left one, it dies. You are given the initial values of the pesticide in each of the plants. Determine the number of days after which no plant dies, i.e. the time after which there is no plan

## AND xor OR

Given an array of distinct elements. Let and be the smallest and the next smallest element in the interval where . . where , are the bitwise operators , and respectively. Your task is to find the maximum possible value of . Input Format First line contains integer N. Second line contains N integers, representing elements of the array A[] . Output Format Print the value