**Nested Lists**

### Problem Statement :

Given the names and grades for each student in a class of N students, store them in a nested list and print the name(s) of any student(s) having the second lowest grade. Note: If there are multiple students with the second lowest grade, order their names alphabetically and print each name on a new line. Example: records=[["chi",20.0], ["beta", 50.0], ["alpha",50.0]] The ordered list of scores is [20.0,50.0] , so the second lowest score is 50.0. There are two students with that score: ["alpha", "beta"]. Ordered alphabetically, the names are printed as: alpha beta Input Format: The first line contains an integer, N , the number of students. The subsequent 2N lines describe each student over 2 lines. - The first line contains a student's name. - The second line contains their grade. Constraints: 2<=N<=5 There will always be one or more students having the second lowest grade. Output Format: Print the name(s) of any student(s) having the second lowest grade in. If there are multiple students, order their names alphabetically and print each one on a new line.

### Solution :

` ````
Solution in C :
if __name__ == '__main__':
lis=[]
for _ in range(int(input())):
name = input()
score = float(input())
lis.append([name,score])
lis.sort(key=lambda lis:lis[1])
second_lowest=[]
for i in range(len(lis)):
if lis[i][1]!=lis[0][1]:
second_lowest.append(lis[i][0])
for j in range(i+1,len(lis)):
if lis[j][1]==lis[i][1]:
second_lowest.append(lis[j][0])
else:
break
break
else:
continue
second_lowest.sort()
for i in second_lowest:
print(i)
```

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