Nested Lists


Problem Statement :


Given the names and grades for each student in a class of N students, store them in a nested list and print the name(s) of any student(s) having the second lowest grade.

Note: If there are multiple students with the second lowest grade, order their names alphabetically and print each name on a new line.

Example:
     records=[["chi",20.0], ["beta", 50.0], ["alpha",50.0]]


The ordered list of scores is [20.0,50.0] , so the second lowest score is 50.0. There are two students with that score: ["alpha", "beta"]. Ordered alphabetically, the names are printed as:  
         alpha
         beta



Input Format:
         The first line contains an integer, N , the number of students.
         The  subsequent 2N lines describe each student over 2 lines.
                      - The first line contains a student's name.
                      - The second line contains their grade.

Constraints:
          2<=N<=5

There will always be one or more students having the second lowest grade.



Output Format:
           Print the name(s) of any student(s) having the second lowest grade in. If there are multiple students, order their names alphabetically and print each one on a new line.


Solution :



title-img 


                            Solution in C :

if __name__ == '__main__':
    lis=[]
    for _ in range(int(input())):
        name = input()
        score = float(input())
        
        lis.append([name,score])
    
    lis.sort(key=lambda lis:lis[1])
    
    second_lowest=[]
    for i in range(len(lis)):
        if lis[i][1]!=lis[0][1]:
            second_lowest.append(lis[i][0])
            for j in range(i+1,len(lis)):
                if lis[j][1]==lis[i][1]:
                    second_lowest.append(lis[j][0])
                else:
                    break
            break        
           
                   
            
        else:
            continue
           

    second_lowest.sort()
    for i in second_lowest:
        print(i)








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