**Maximize Binary String Score - Google Top Interview Questions**

### Problem Statement :

You are given a binary string s containing "1"s and "0"s. Consider splitting the string into two non-empty substrings such that a + b = s. The score of this split is defined to be the sum of the number of "0"s in a plus the number of "1"s in b. Return the maximum score possible. Constraints 2 ≤ n ≤ 100,000 where n is the length of s Example 1 Input s = "001001110111" Output 10 Explanation We can split the string into "00100" + "1110111". Then, the score is 4 + 6 = 10`.

### Solution :

` ````
Solution in C++ :
int solve(string s) {
int left_zeroes = 0, right_ones = 0;
for (auto &ch : s) {
right_ones += ch == '1';
}
int ans = 0;
for (int i = 0; i < s.length() - 1; i++) {
right_ones -= s[i] == '1';
left_zeroes += s[i] == '0';
ans = max(ans, left_zeroes + right_ones);
}
return ans;
}
```

` ````
Solution in Java :
class Solution {
public int solve(String s) {
int c1 = 0;
for (char c : s.toCharArray()) {
if (c == '1')
c1++;
}
int max = 0, curr = c1;
if (c1 == 0 || c1 == s.length())
return s.length() - 1;
for (int i = 0; i < s.length() - 1; i++) {
char c = s.charAt(i);
if (c == '0') {
curr++;
} else
curr--;
max = Math.max(max, curr);
}
return max;
}
}
```

` ````
Solution in Python :
class Solution:
def solve(self, s):
ones = s.count("1")
zeros = 0
ans = 0
for i in range(len(s) - 1):
if s[i] == "0":
zeros += 1
else:
ones -= 1
ans = max(ans, ones + zeros)
return ans
```

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