# Lists

### Problem Statement :

Consider a list (list = []). You can perform the following commands:

1. insert i e: Insert integer e at position i.
2. print: Print the list.
3. remove e: Delete the first occurrence of integer e .
4. append e: Insert integer e at the end of the list.
5. sort: Sort the list.
6. pop: Pop the last element from the list.
7. reverse: Reverse the list
.
Initialize your list and read in the value of n followed by n lines of commands where each command will be of the 7 types listed above. Iterate through each command in order and perform the corresponding operation on your list.

Example:
N=4
append 1
append 2
insert 3 1
print
1. append 1: Append 1 to the list, arr=[1].
2. append 2 :append 2 to the list, arr=[1,2]
3. insert 3 1: Insert 3 at insex 1  , arr=[1,3,2]
4. print: print the array

Output:
[1, 3, 2]

Input Format:
The first line contains an integer, n, denoting the number of commands.
Each line i of the n subsequent lines contains one of the commands described above.

Constraints:
The elements added to the list must be integers.

Output Format:
For each command of type print, print the list on a new line.

### Solution :

Solution in C :

if __name__ == '__main__':
N = int(input())
command=[]
for i in range(N):
command.append(input().split())

result=[]
for i in range(N):
if command[i][0]=='insert':
result.insert(int(command[i][1]),int(command[i][2]))
elif command[i][0]=='print':
print(result)
elif command[i][0]=='remove':
result.remove(int(command[i][1]))
elif command[i][0]=='append':
result.append(int(command[i][1]))
elif command[i][0]=='pop':
result.pop()
elif command[i][0]=='sort':
result.sort()
elif command[i][0]=='reverse':
result.reverse()

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