**Lists**

### Problem Statement :

Consider a list (list = []). You can perform the following commands: 1. insert i e: Insert integer e at position i. 2. print: Print the list. 3. remove e: Delete the first occurrence of integer e . 4. append e: Insert integer e at the end of the list. 5. sort: Sort the list. 6. pop: Pop the last element from the list. 7. reverse: Reverse the list . Initialize your list and read in the value of n followed by n lines of commands where each command will be of the 7 types listed above. Iterate through each command in order and perform the corresponding operation on your list. Example: N=4 append 1 append 2 insert 3 1 print 1. append 1: Append 1 to the list, arr=[1]. 2. append 2 :append 2 to the list, arr=[1,2] 3. insert 3 1: Insert 3 at insex 1 , arr=[1,3,2] 4. print: print the array Output: [1, 3, 2] Input Format: The first line contains an integer, n, denoting the number of commands. Each line i of the n subsequent lines contains one of the commands described above. Constraints: The elements added to the list must be integers. Output Format: For each command of type print, print the list on a new line.

### Solution :

` ````
Solution in C :
if __name__ == '__main__':
N = int(input())
command=[]
for i in range(N):
command.append(input().split())
result=[]
for i in range(N):
if command[i][0]=='insert':
result.insert(int(command[i][1]),int(command[i][2]))
elif command[i][0]=='print':
print(result)
elif command[i][0]=='remove':
result.remove(int(command[i][1]))
elif command[i][0]=='append':
result.append(int(command[i][1]))
elif command[i][0]=='pop':
result.pop()
elif command[i][0]=='sort':
result.sort()
elif command[i][0]=='reverse':
result.reverse()
```

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