Invert Tree - Amazon Top Interview Questions
Problem Statement :
Given a binary tree root, invert it so that its left subtree and right subtree are swapped and the children are recursively inverted. Constraints n ≤ 100,000 where n is the number of nodes in root Example 1 Input root = [0, [2, null, null], [9, [7, null, null], [12, null, null]]] Output [0, [9, [12, null, null], [7, null, null]], [2, null, null]]
Solution :
Solution in C++ :
Tree* solve(Tree* root) {
if (root == nullptr) {
return root;
}
queue<Tree*> q;
q.push(root);
while (!q.empty()) {
Tree* curr = q.front();
q.pop();
// swapping left and right nodes
Tree* temp = curr->left;
curr->left = curr->right;
curr->right = temp;
if (curr->left != nullptr) {
q.push(curr->left);
}
if (curr->right != nullptr) {
q.push(curr->right);
}
}
return root;
}
Solution in Java :
import java.util.*;
/**
* public class Tree {
* int val;
* Tree left;
* Tree right;
* }
*/
class Solution {
public Tree solve(Tree root) {
return mirror(root);
}
static Tree mirror(Tree root) {
if (root == null)
return null;
Tree left = mirror(root.left);
Tree right = mirror(root.right);
root.left = right;
root.right = left;
return root;
}
}
Solution in Python :
class Solution:
def solve(self, root):
if root:
dq = deque([root])
while dq:
node = dq.popleft()
node.left, node.right = node.right, node.left
if node.left:
dq.append(node.left)
if node.right:
dq.append(node.right)
return root
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