**Inserting a Node Into a Sorted Doubly Linked List**

### Problem Statement :

Given a reference to the head of a doubly-linked list and an integer ,data , create a new DoublyLinkedListNode object having data value data and insert it at the proper location to maintain the sort. Example head refers to the list 1 <-> 2 <-> 4 - > NULL. data = 3 Return a reference to the new list: 1 <-> 2 <-> 4 - > NULL , Function Description Complete the sortedInsert function in the editor below. sortedInsert has two parameters: DoublyLinkedListNode pointer head: a reference to the head of a doubly-linked list int data: An integer denoting the value of the data field for the DoublyLinkedListNode you must insert into the list. Returns DoublyLinkedListNode pointer: a reference to the head of the list Note: Recall that an empty list (i.e., where head = NULL ) and a list with one element are sorted lists. nput Format The first line contains an integer t, the number of test cases. Each of the test case is in the following format: The first line contains an integer n, the number of elements in the linked list. Each of the next n lines contains an integer, the data for each node of the linked list. The last line contains an integer, data , which needs to be inserted into the sorted doubly-linked list.

### Solution :

` ````
Solution in C :
In C :
// Complete the sortedInsert function below.
/*
* For your reference:
*
* DoublyLinkedListNode {
* int data;
* DoublyLinkedListNode* next;
* DoublyLinkedListNode* prev;
* };
*
*/
DoublyLinkedListNode* sortedInsert(DoublyLinkedListNode* head, int data) {
DoublyLinkedListNode *New = create_doubly_linked_list_node(data);
if (!head)
{
head = New;
return head;
}
else if (data < (head->data))
{
New->next = head;
head->prev = New;
New->prev = NULL;
head = New;
return head;
}
else
{
DoublyLinkedListNode *temp = head;
while ( ((temp->next) != NULL) && ((temp->next->data) <= data))
temp = temp->next;
if (temp->next != NULL)
{
DoublyLinkedListNode *next = temp->next;
next->prev = New;
New->next = next;
}
else
New->next = NULL;
temp->next = New;
New->prev = temp;
}
return head;
}
```

` ````
Solution in C++ :
In C++ :
/*
Insert Node in a doubly sorted linked list
After each insertion, the list should be sorted
Node is defined as
struct Node
{
int data;
Node *next;
Node *prev
}
*/
Node* SortedInsert(Node *head,int data)
{
// Complete this function
// Do not write the main method.
Node *current = NULL;
Node *new_node = (Node*)malloc(sizeof(Node));
new_node->data=data;
new_node->next=NULL;
new_node->prev=NULL;
if (head == NULL )
{
head = new_node;
}
else if(head->data >= new_node->data)
{
new_node->next = head;
head->prev=new_node;
head = new_node;
}
else
{
current = head;
while (current->next!=NULL && current->next->data < new_node->data)
{
current = current->next;
}
if(current->next!=NULL)
{
new_node->next = current->next;
current->next->prev=new_node;
}
current->next = new_node;
new_node->prev=current;
}
return head;
}
```

` ````
Solution in Java :
In Java :
/*
Insert Node at the end of a linked list
head pointer input could be NULL as well for empty list
Node is defined as
class Node {
int data;
Node next;
Node prev;
}
*/
Node SortedInsert(Node head,int data) {
Node n= new Node();
n.data=data;
n.next=null;
n.prev=null;
if(head==null)
return n;
if(head.data > data)
{
n.next=head;
head.prev=n;
return n;
}
Node temp=head;
while(temp.next!=null)
{
if(temp.next.data > data)
{
n.next=temp.next;
n.prev=temp.next.prev;
temp.next=n;
n.next.prev=n;
return head;
}
temp=temp.next;
}
temp.next=n;
n.prev=temp;
return head;
}
```

` ````
Solution in Python :
In python3 :
"""
Insert a node into a sorted doubly linked list
head could be None as well for empty list
Node is defined as
class Node(object):
def __init__(self, data=None, next_node=None, prev_node = None):
self.data = data
self.next = next_node
self.prev = prev_node
return the head node of the updated list
"""
def SortedInsert(head, data):
new = Node(data=data)
tmp = head
while tmp.data <= data and tmp.next != None and tmp.next.data <= data:
tmp = tmp.next
new.prev = tmp
new.next = tmp.next
tmp.next = new
if new.next != None:
new.next.prev = new
return head
```

## View More Similar Problems

## Self Balancing Tree

An AVL tree (Georgy Adelson-Velsky and Landis' tree, named after the inventors) is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than one, rebalancing is done to restore this property. We define balance factor for each node as : balanceFactor = height(left subtree) - height(righ

View Solution →## Array and simple queries

Given two numbers N and M. N indicates the number of elements in the array A[](1-indexed) and M indicates number of queries. You need to perform two types of queries on the array A[] . You are given queries. Queries can be of two types, type 1 and type 2. Type 1 queries are represented as 1 i j : Modify the given array by removing elements from i to j and adding them to the front. Ty

View Solution →## Median Updates

The median M of numbers is defined as the middle number after sorting them in order if M is odd. Or it is the average of the middle two numbers if M is even. You start with an empty number list. Then, you can add numbers to the list, or remove existing numbers from it. After each add or remove operation, output the median. Input: The first line is an integer, N , that indicates the number o

View Solution →## Maximum Element

You have an empty sequence, and you will be given N queries. Each query is one of these three types: 1 x -Push the element x into the stack. 2 -Delete the element present at the top of the stack. 3 -Print the maximum element in the stack. Input Format The first line of input contains an integer, N . The next N lines each contain an above mentioned query. (It is guaranteed that each

View Solution →## Balanced Brackets

A bracket is considered to be any one of the following characters: (, ), {, }, [, or ]. Two brackets are considered to be a matched pair if the an opening bracket (i.e., (, [, or {) occurs to the left of a closing bracket (i.e., ), ], or }) of the exact same type. There are three types of matched pairs of brackets: [], {}, and (). A matching pair of brackets is not balanced if the set of bra

View Solution →## Equal Stacks

ou have three stacks of cylinders where each cylinder has the same diameter, but they may vary in height. You can change the height of a stack by removing and discarding its topmost cylinder any number of times. Find the maximum possible height of the stacks such that all of the stacks are exactly the same height. This means you must remove zero or more cylinders from the top of zero or more of

View Solution →