Grading Students


Problem Statement :


HackerLand University has the following grading policy:

   1. Every student receives a grade in the inclusive range from 1 to 100.
   2. Any grade less than 30 is a failing grade. 

     

Sam is a professor at the university and likes to round each student's grade according to these rules:

  1.If the difference between the grade and the next multiple of 5 is less than 3 , round up to the next multiple of 5.
  2.If the value of grade  is less than 38 , no rounding occurs as the result will still be a failing grade.

Examples

  1. grade = 84 round to85 (85 - 84 is less than 3)
  2. grade = 29 do not round (result is less than 40)
  3. grade = do not round (60 - 57 is 3 or higher)

Given the initial value of  grade for each of Sam's n students, write code to automate the rounding 
process. 

Function Description

Complete the function gradingStudents in the editor below.

gradingStudents has the following parameter(s):

    int grades[n]: the grades before rounding

Returns

    int[n]: the grades after rounding as appropriate

Input Format

The first line contains a single integer,n , the number of students.
Each line i of the n subsequent lines contains a single integer, grades[i].

Constraints
  
  1<= n < =60
  0 <= grades[i] <= 100


Solution :



title-img 


                            Solution in C :

In C :

int* gradingStudents(int grades_count, int* grades, int* result_count) {
    
   static int my_grades[10];
    for(int i = 0;  i< grades_count ; i++)
    {
        if(grades[i] < 38) my_grades[i] = grades[i];
        else if((grades[i] % 5)==0) my_grades[i] = grades[i];
        else
         {
             int num = grades[i];
             int num2 = grades[i];
             while((num % 5) !=0)
             {
                num = num +1;
             } 
             
        
             if((num-num2) < 3) my_grades[i] = num;
             else my_grades[i] = num2;

        }
    }
    

    *result_count = grades_count;
    return my_grades;
}




In C ++ :


#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <bitset>
#include <cstdio>
#include <limits>
#include <vector>
#include <climits>
#include <cstring>
#include <cstdlib>
#include <fstream>
#include <numeric>
#include <sstream>
#include <iostream>
#include <algorithm>
#include <unordered_map>

using namespace std;


int main(){
    int n;
    cin >> n;
    for(int a0 = 0; a0 < n; a0++){
        int grade;
        cin >> grade;
        if (grade >= 38) {
            int rem = grade % 5;
            if (rem >= 3) grade += 5 - rem;
        }
        cout << grade << endl;
    }
    return 0;
}




In Java :


import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        for(int a0 = 0; a0 < n; a0++){
            int grade = in.nextInt();
            if (grade >= 38) {
                if (grade % 5 >= 3) {
                    grade += 5 - (grade % 5);
                }
            }
            System.out.println(grade);
        }
    }
}




In Python3 :


#!/bin/python3

import sys


n = int(input().strip())
for a0 in range(n):
    x = int(input().strip())
    
    if x >= 38:
        if x % 5 > 2:
            while x % 5 != 0: x += 1
    print(x)








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