Extra long Factorials

Problem Statement :

The factorial of the integer n, written n!, is defined as:
         n! = n * (n-1) * (n-2) * ........ * 3 * 2 * 1
Calculate and print the factorial of a given integer.

For example, if n = 30, we calculate 30 * 29 * 28 * ...... * 3 * 2 * 1 and get 265252859812191058636308480000000.

Function Description

Complete the extraLongFactorials function in the editor below. It should print the result and return.
extraLongFactorials has the following parameter(s):
n: an integer

Note: Factorials of  can't be stored even in a  long long variable. Big integers must be used for such calculations. Languages like Java, Python, Ruby etc. can handle big integers, but we need to write additional code in C/C++ to handle huge values.

We recommend solving this challenge using BigIntegers.

Input Format

Input consists of a single integer n

1 <= n <= 100

Output Format

Print the factorial of n.

Solution :


                            Solution in C :

python 3  :

from math import factorial

Java  :

import java.io.*;
import java.util.*;
import java.math.BigInteger;

public class Solution {

    public static void main(String[] args) {
        int N,i;
            Scanner in=new Scanner(System.in);
        BigInteger res=BigInteger.ONE;
       res = res.multiply(BigInteger.valueOf(i));

C ++  :

using namespace std;

int main(void)
    int i=0,j=0,fact[20000],k=0,l=0,n=0,temp=0;


     return 0;

C  :

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() { int t; int a[200];   int n,i,j,temp,m,x;
   temp = 0; 
           x = a[j]*i+temp; 
           temp = x/10; 
           temp = temp/10;

return 0;

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