**Delete Integers In Ascending Order - Google Top Interview Questions**

### Problem Statement :

You are given a list of unique integers nums and want to delete each number in ascending order. Return the indices of numbers in order of their deletion. Constraints n ≤ 100,000 where n is the length of nums Example 1 Input nums = [3, 5, 1, 4, 2] Output [2, 3, 0, 1, 0] Explanation We delete the numbers in this order: Delete 1 at index 2 and now we have [3, 5, 4, 2] Delete 2 at index 3 and now we have [3, 5, 4] Delete 3 at index 0 and now we have [5, 4] Delete 4 at index 1 and now we have [5] Delete 5 at index 0 and now we have []

### Solution :

` ````
Solution in C++ :
const int SZ = 1 << 17;
void upd(vector<int>& tree, int idx, int val) {
idx += SZ;
while (idx) {
tree[idx] += val;
idx /= 2;
}
}
int qry(vector<int>& tree, int lhs, int rhs) {
lhs += SZ;
rhs += SZ;
int ret = 0;
while (lhs <= rhs) {
if (lhs % 2) ret += tree[lhs++];
if (rhs % 2 == 0) ret += tree[rhs--];
lhs /= 2;
rhs /= 2;
}
return ret;
}
vector<int> solve(vector<int>& nums) {
vector<int> tree(2 * SZ);
int n = nums.size();
vector<int> ret;
vector<pair<int, int>> pairs;
for (int i = 0; i < n; i++) pairs.emplace_back(nums[i], i);
sort(pairs.begin(), pairs.end());
for (auto p : pairs) {
ret.push_back(p.second - qry(tree, 0, p.second - 1));
upd(tree, p.second, 1);
}
return ret;
}
```

` ````
Solution in Java :
import java.util.*;
class Solution {
class SegTree {
int leftMost, rightMost, sum;
SegTree left, right;
int[] a;
public SegTree(int[] a, int leftMost, int rightMost) {
this.a = a;
this.leftMost = leftMost;
this.rightMost = rightMost;
int mid = (rightMost + leftMost) / 2;
if (leftMost == rightMost) {
sum = a[leftMost];
} else {
left = new SegTree(a, leftMost, mid);
right = new SegTree(a, mid + 1, rightMost);
recalc();
}
}
void recalc() {
if (leftMost == rightMost)
return;
sum = right.sum + left.sum;
}
void pointUpdate(int index, int newVal) {
if (leftMost == rightMost) {
sum = newVal;
return;
}
if (index <= left.rightMost)
left.pointUpdate(index, newVal);
else
right.pointUpdate(index, newVal);
recalc();
}
int rangeSum(int l, int r) {
// three cases:
// 1. no intersect
if (r < leftMost || rightMost < l)
return 0;
// 2. partially contained
if (l <= leftMost && r >= rightMost)
return sum;
// 3. don't know
return left.rangeSum(l, r) + right.rangeSum(l, r);
}
}
int[] solve(int[] nums) {
List<int[]> ls = new ArrayList<>();
int[] res = new int[nums.length];
if (nums.length == 0)
return res;
for (int i = 0; i < nums.length; i++) {
ls.add(new int[] {nums[i], i});
}
Collections.sort(ls, (a, b) -> a[0] - b[0]);
SegTree segTree = new SegTree(new int[nums.length], 0, nums.length - 1);
for (int i = 0; i < nums.length; i++) {
int[] n = ls.get(i);
int index = n[1];
int rangeSum = segTree.rangeSum(0, index);
res[i] = index - rangeSum;
segTree.pointUpdate(index, 1);
}
return res;
}
}
```

` ````
Solution in Python :
class Solution:
def solve(self, nums):
# indices holds pairs (index, number)
indices = list(enumerate(nums))
indices.sort(key=lambda x: -x[1])
sl = SortedList()
result = []
for idx, _ in indices:
t = sl.bisect_left(idx)
result.append(t)
sl.add(idx)
return result[::-1]
```

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