**Condition Statements in c**

### Problem Statement :

Task: Given a positive integer denoting n, do the following: If 1<=n<=9, print the lowercase English word corresponding to the number (e.g., one for 1, two for 2, etc.). If n>9, print Greater than 9. Input Format: The first line contains a single integer, n. Constraints: 1<=n<=10^9 Output Format: If 1<=n<=9, then print the lowercase English word corresponding to the number (e.g., one for 1, two for 2, etc.); otherwise, print Greater than 9 instead.

### Solution :

` ````
Solution in C :
#include <stdio.h>
int main()
{
int n;
scanf("%d",&n);
// Your code goes here.
if (n == 1) {
printf("one\n");
} else if (n == 2) {
printf("two\n");
} else if (n == 3) {
printf("three\n");
} else if (n == 4) {
printf("four\n");
} else if (n == 5) {
printf("five\n");
} else if (n == 6) {
printf("six\n");
} else if (n == 7) {
printf("seven\n");
} else if (n == 8) {
printf("eight\n");
} else if (n == 9) {
printf("nine\n");
} else {
printf("Greater than 9\n");
}
return 0;
}
```

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