Condition Statements in c


Problem Statement :


Task:

Given a positive integer denoting n, do the following:

If 1<=n<=9, print the lowercase English word corresponding to the number (e.g., one for 1, two for 2, etc.).
If n>9, print Greater than 9.


Input Format:

The first line contains a single integer, n.


Constraints:
1<=n<=10^9


Output Format:

If 1<=n<=9, then print the lowercase English word corresponding to the number (e.g., one for 1, two for 2, etc.); otherwise, print Greater than 9 instead.


Solution :



title-img 


                            Solution in C :

#include <stdio.h>

int main()
{
    int n; 
    scanf("%d",&n);
    // Your code goes here.
    if (n == 1) {
        printf("one\n");
    } else if (n == 2) {
        printf("two\n");
    } else if (n == 3) {
        printf("three\n");
    } else if (n == 4) {
        printf("four\n");
    } else if (n == 5) {
        printf("five\n");
    } else if (n == 6) {
        printf("six\n");
    } else if (n == 7) {
        printf("seven\n");
    } else if (n == 8) {
        printf("eight\n");
    } else if (n == 9) {
        printf("nine\n");
    } else {
        printf("Greater than 9\n");
    }
     
    
    return 0;
}








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