C++ Class Template Specialization
Problem Statement :
You are given a main function which reads the enumeration values for two different types as input, then prints out the corresponding enumeration names. Write a class template that can provide the names of the enumeration values for both types. If the enumeration value is not valid, then print unknown. Input Format The first line contains t , the number of test cases. Each of the t subsequent lines contains two space-separated integers. The first integer is a color value, c, and the second integer is a fruit value, f. Constraints 1 <= t <= 100 -2 x 10^9 <= c <= 2 x 10^9 -2 x 10^9 <= f <= 2 x 10^9 Output Format The locked stub code in your editor prints t lines containing the color name and the fruit name corresponding to the input enumeration index.
Solution :
Solution in C :
#include <string>
template <typename T> struct Traits
{
static std::string name(int index) { return "unknown"; }
};
template<> struct Traits<Fruit>
{
static std::string name(int index)
{
switch((Fruit)index) {
case Fruit::apple: return "apple";
case Fruit::orange: return "orange";
case Fruit::pear: return "pear";
default: return "unknown";
}
}
};
template<> struct Traits<Color>
{
static std::string name(int index)
{
switch((Color)index) {
case Color::red: return "red";
case Color::green: return "green";
case Color::orange: return "orange";
default: return "unknown";
}
}
};
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