CamelCase


Problem Statement :


There is a sequence of words in CamelCase as a string of letters, s, having the following properties:

It is a concatenation of one or more words consisting of English letters.
All letters in the first word are lowercase.
For each of the subsequent words, the first letter is uppercase and rest of the letters are lowercase.

Given s, determine the number of words in s.

Function Description

Complete the camelcase function in the editor below.

camelcase has the following parameter(s):

string s: the string to analyze


Returns

int: the number of words in s


Input Format

A single line containing string s.


Constraints


1  <=  length of s  <=   10^5


Sample Input

saveChangesInTheEditor


Sample Output

5


Solution :



title-img 


                            Solution in C :

In   C++   :






#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> ii;

int main() {
    string s;
    cin>>s;
    int count = 1;
    for (const char c : s) {
        if (c >= 'A' && c <= 'Z')
            ++count;
    }
    cout<<count<<endl;
}








In  Java  :




import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String s = in.next();
        int count = 1;
        for(int i = 0; i<s.length(); i++){
            char c = s.charAt(i);
            if(c>='A' && c<='Z') count++;
        }
        System.out.println(count);
    }
}









In   C  :






#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int main(){
    char* s = (char *)malloc(10240 * sizeof(char));
    scanf("%s",s);
    int coun=0,i;
    for(i=0;i<strlen(s);i++)
    {
        if(s[i]>=65 && s[i]<=90){coun++;}
    }
    printf("%d\n",coun+1);
    return 0;
}








In   Python3  :




t = input()
uppercase = [x for x in t if x.isupper()]
print(len(uppercase)+1)








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