**Any or All python**

### Problem Statement :

any() This expression returns True if any element of the iterable is true. If the iterable is empty, it will return False. Code >>> any([1>0,1==0,1<0]) True >>> any([1<0,2<1,3<2]) False all() This expression returns True if all of the elements of the iterable are true. If the iterable is empty, it will return True. Code >>> all(['a'<'b','b'<'c']) True >>> all(['a'<'b','c'<'b']) False Task You are given a space separated list of integers. If all the integers are positive, then you need to check if any integer is a palindromic integer. Input Format The first line contains an integer N. N is the total number of integers in the list. The second line contains the space separated list of N integers. Constraints 0<N<100 Output Format Print True if all the conditions of the problem statement are satisfied. Otherwise, print False.

### Solution :

` ````
Solution in C :
n = int(input())
numbers = list(map(int,input().split()))
count = 0
count_palindrome = 0
for element in numbers:
if element > 0:
count += 1
for i in range(len(numbers)):
string = str(numbers[i])
counts = 0
for j in range(len(string)//2):
if string[j] == string[-1-j]:
counts += 1
if counts == len(string)//2:
count_palindrome += 1
if count_palindrome > 0 and count ==len(numbers):
print(True)
else:
print(False)
```

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