Any or All python

Problem Statement :

This expression returns True if any element of the iterable is true.
If the iterable is empty, it will return False.


>>> any([1>0,1==0,1<0])
>>> any([1<0,2<1,3<2])
This expression returns True if all of the elements of the iterable are true. If the iterable is empty, it will return True.


>>> all(['a'<'b','b'<'c'])
>>> all(['a'<'b','c'<'b'])


You are given a space separated list of integers. If all the integers are positive, then you need to check if any integer is a palindromic integer.

Input Format

The first line contains an integer N. N is the total number of integers in the list.
The second line contains the space separated list of N integers.


Output Format

Print True if all the conditions of the problem statement are satisfied. Otherwise, print False.

Solution :


                            Solution in C :

n = int(input())
numbers = list(map(int,input().split()))
count = 0
count_palindrome = 0
for element in numbers:
    if element > 0:
        count += 1
for i in range(len(numbers)):
    string = str(numbers[i])
    counts = 0
    for j in range(len(string)//2):
        if string[j] == string[-1-j]:
            counts += 1
    if counts == len(string)//2:
        count_palindrome += 1
if count_palindrome > 0 and count ==len(numbers):

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